18 lines
306 B
Ruby
18 lines
306 B
Ruby
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def spiral(size)
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max_value = size**2
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diagonals = [1]
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diagonal_increase_value = 2
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current_num = 1
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until current_num == max_value
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4.times do
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current_num += diagonal_increase_value
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diagonals << current_num
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end
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diagonal_increase_value += 2
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end
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diagonals.inject(:+)
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end
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